The Conservative Cave

The Bar => The Lounge => Topic started by: Chris_ on February 27, 2008, 10:39:29 PM

Title: Math Drama
Post by: Chris_ on February 27, 2008, 10:39:29 PM

Can anyone solve this, showing their work?

The j should be in italics, it's the engineering version of the imaginary i.
(http://i46.photobucket.com/albums/f144/Chesterfield313/MATH.jpg)

Title: Re: Math Drama
Post by: Chris_ on February 27, 2008, 10:59:12 PM

    * Step 1: -1/1 = 1/-1

    * Step 2: Taking the square root of both sides: (http://www.math.toronto.edu/mathnet/falseProofs/fallacies_hlimgs/image24.gif)

    * Step 3: Simplifying: (http://www.math.toronto.edu/mathnet/falseProofs/fallacies_hlimgs/image25.gif)

    * Step 4: In other words, i/1 = 1/i.

    * Step 5: Therefore, i / 2 = 1 / (2i),

    * Step 6: i/2 + 3/(2i) = 1/(2i) + 3/(2i),

    * Step 7: i (i/2 + 3/(2i) ) = i ( 1/(2i) + 3/(2i) ),

    * Step 8: (IMAGE) ,

    * Step 9: (-1)/2 + 3/2 = 1/2 + 3/2,

    * Step 10: and this shows that 1=2.

Title: Re: Math Drama
Post by: mamacags on February 28, 2008, 08:43:26 AM

Quote from: Vonne on February 27, 2008, 10:39:29 PM

Can anyone solve this, showing their work?

The j should be in italics, it's the engineering version of the imaginary i.
(http://i46.photobucket.com/albums/f144/Chesterfield313/MATH.jpg)

OK this is my answer but remember I am not very good at math.........

Sub prime 234342% =j=r=45
triangle Xpi r squared =234
minus the subcutanious alfalfa of the linear line
the answer is 5