The Conservative Cave

The Bar => The Lounge => Topic started by: SSG Snuggle Bunny on February 12, 2009, 07:45:25 PM

Title: Viva Capitalism!
Post by: SSG Snuggle Bunny on February 12, 2009, 07:45:25 PM
I'll be the first to admit math is not my strong suit; but, despite it's predominantly blue-collar foundation, working in the oilfields requires copious amounts of math, i.e.:

The well-bore has an annulus of 8.75" diameter that is cased with 11.6#/ft. iron with an outside diameter of 6" and an inside diameter of 4 5/8" to a depth of 5670 ft. How many barrels of cementing fluid would be required to cement the annular space while leaving a 60' shoe?

Halliburton has an expansive employee training database complete with inline testing. Today I took took a test consisting of 40 such problems and scored 90%. I am now being deluged with offers to take the test on behalf of various crew-mates with offers ranging from $20 to $50...plus the odd case of beer.

I love this country.
Title: Re: Viva Capitalism!
Post by: RobJohnson on February 13, 2009, 02:49:59 AM

The story problem that you posted makes my head hurt just by reading it!

What is the answer? Please show your work.

Title: Re: Viva Capitalism!
Post by: Thor on February 13, 2009, 07:33:45 AM
I believe that it has to do with measuring the volume of two or three cylinders.
Title: Re: Viva Capitalism!
Post by: SSG Snuggle Bunny on February 13, 2009, 07:57:15 AM
I believe that it has to do with measuring the volume of two or three cylinders.
Pretty much.

Convert all inch measurements to feet. You compute the volume for the annular space first then subtract from that the volume of the casing based on the OUTER diameter. Then add to that a volume based on the casing's INNER diameter up to a height of 60' (the so-called "shoe" at the bottom of the casing). That's how many cubic feet of cementing material you need but since the problem asks for barrels (42 gallons) you multiply by 0.1781.

The pounds/foot weight for the casing is just a distractor deliberately added to see if people can seperate valid info from extraneous info for a given type of problem...although it does come in later during buoyancy calculations and weights to be placed on the drill bit etc.

Ironically, the transplanted Californians around here look down their noses at "oilfield trash" because we're supposed to be a bunch of ignorant brutes. It seems the only ignorance is theirs.
Title: Re: Viva Capitalism!
Post by: JohnnyReb on February 13, 2009, 09:07:42 AM

Ironically, the transplanted Californians around here look down their noses at "oilfield trash" because we're supposed to be a bunch of ignorant brutes. It seems the only ignorance is theirs.

Education teaches you the tools to use....practical experience teaches you how to use them.


Title: Re: Viva Capitalism!
Post by: Chris_ on February 13, 2009, 01:24:39 PM
Pretty much.

Convert all inch measurements to feet. You compute the volume for the annular space first then subtract from that the volume of the casing based on the OUTER diameter. Then add to that a volume based on the casing's INNER diameter up to a height of 60' (the so-called "shoe" at the bottom of the casing). That's how many cubic feet of cementing material you need but since the problem asks for barrels (42 gallons) you multiply by 0.1781.

The pounds/foot weight for the casing is just a distractor deliberately added to see if people can seperate valid info from extraneous info for a given type of problem...although it does come in later during buoyancy calculations and weights to be placed on the drill bit etc.

Ironically, the transplanted Californians around here look down their noses at "oilfield trash" because we're supposed to be a bunch of ignorant brutes. It seems the only ignorance is theirs.

I am not an oilman, but when it was talking about diameters my first thought was "they are talking volume -- who cares about the outside casing?"  Good to know I was right (in this case anyway).